Optimal. Leaf size=207 \[ \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3 \tanh ^{-1}\left (1-\frac {2}{1-c x^2}\right )-\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {PolyLog}\left (2,1-\frac {2}{1-c x^2}\right )+\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {PolyLog}\left (2,-1+\frac {2}{1-c x^2}\right )+\frac {3}{4} b^2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {PolyLog}\left (3,1-\frac {2}{1-c x^2}\right )-\frac {3}{4} b^2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {PolyLog}\left (3,-1+\frac {2}{1-c x^2}\right )-\frac {3}{8} b^3 \text {PolyLog}\left (4,1-\frac {2}{1-c x^2}\right )+\frac {3}{8} b^3 \text {PolyLog}\left (4,-1+\frac {2}{1-c x^2}\right ) \]
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Rubi [A]
time = 0.37, antiderivative size = 207, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 7, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.438, Rules used = {6035, 6033,
6199, 6095, 6205, 6209, 6745} \begin {gather*} \frac {3}{4} b^2 \text {Li}_3\left (1-\frac {2}{1-c x^2}\right ) \left (a+b \tanh ^{-1}\left (c x^2\right )\right )-\frac {3}{4} b^2 \text {Li}_3\left (\frac {2}{1-c x^2}-1\right ) \left (a+b \tanh ^{-1}\left (c x^2\right )\right )-\frac {3}{4} b \text {Li}_2\left (1-\frac {2}{1-c x^2}\right ) \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2+\frac {3}{4} b \text {Li}_2\left (\frac {2}{1-c x^2}-1\right ) \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2+\tanh ^{-1}\left (1-\frac {2}{1-c x^2}\right ) \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3-\frac {3}{8} b^3 \text {Li}_4\left (1-\frac {2}{1-c x^2}\right )+\frac {3}{8} b^3 \text {Li}_4\left (\frac {2}{1-c x^2}-1\right ) \end {gather*}
Antiderivative was successfully verified.
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Rule 6033
Rule 6035
Rule 6095
Rule 6199
Rule 6205
Rule 6209
Rule 6745
Rubi steps
\begin {align*} \int \frac {\left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3}{x} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {\left (a+b \tanh ^{-1}(c x)\right )^3}{x} \, dx,x,x^2\right )\\ &=\left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3 \tanh ^{-1}\left (1-\frac {2}{1-c x^2}\right )-(3 b c) \text {Subst}\left (\int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2 \tanh ^{-1}\left (1-\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx,x,x^2\right )\\ &=\left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3 \tanh ^{-1}\left (1-\frac {2}{1-c x^2}\right )+\frac {1}{2} (3 b c) \text {Subst}\left (\int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx,x,x^2\right )-\frac {1}{2} (3 b c) \text {Subst}\left (\int \frac {\left (a+b \tanh ^{-1}(c x)\right )^2 \log \left (2-\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx,x,x^2\right )\\ &=\left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3 \tanh ^{-1}\left (1-\frac {2}{1-c x^2}\right )-\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {Li}_2\left (1-\frac {2}{1-c x^2}\right )+\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {Li}_2\left (-1+\frac {2}{1-c x^2}\right )+\frac {1}{2} \left (3 b^2 c\right ) \text {Subst}\left (\int \frac {\left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (1-\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx,x,x^2\right )-\frac {1}{2} \left (3 b^2 c\right ) \text {Subst}\left (\int \frac {\left (a+b \tanh ^{-1}(c x)\right ) \text {Li}_2\left (-1+\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx,x,x^2\right )\\ &=\left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3 \tanh ^{-1}\left (1-\frac {2}{1-c x^2}\right )-\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {Li}_2\left (1-\frac {2}{1-c x^2}\right )+\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {Li}_2\left (-1+\frac {2}{1-c x^2}\right )+\frac {3}{4} b^2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {Li}_3\left (1-\frac {2}{1-c x^2}\right )-\frac {3}{4} b^2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {Li}_3\left (-1+\frac {2}{1-c x^2}\right )-\frac {1}{4} \left (3 b^3 c\right ) \text {Subst}\left (\int \frac {\text {Li}_3\left (1-\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx,x,x^2\right )+\frac {1}{4} \left (3 b^3 c\right ) \text {Subst}\left (\int \frac {\text {Li}_3\left (-1+\frac {2}{1-c x}\right )}{1-c^2 x^2} \, dx,x,x^2\right )\\ &=\left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3 \tanh ^{-1}\left (1-\frac {2}{1-c x^2}\right )-\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {Li}_2\left (1-\frac {2}{1-c x^2}\right )+\frac {3}{4} b \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {Li}_2\left (-1+\frac {2}{1-c x^2}\right )+\frac {3}{4} b^2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {Li}_3\left (1-\frac {2}{1-c x^2}\right )-\frac {3}{4} b^2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {Li}_3\left (-1+\frac {2}{1-c x^2}\right )-\frac {3}{8} b^3 \text {Li}_4\left (1-\frac {2}{1-c x^2}\right )+\frac {3}{8} b^3 \text {Li}_4\left (-1+\frac {2}{1-c x^2}\right )\\ \end {align*}
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Mathematica [A]
time = 0.13, size = 211, normalized size = 1.02 \begin {gather*} \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^3 \tanh ^{-1}\left (1+\frac {2}{-1+c x^2}\right )+\frac {3}{8} b \left (2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {PolyLog}\left (2,\frac {1+c x^2}{1-c x^2}\right )-2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right )^2 \text {PolyLog}\left (2,\frac {1+c x^2}{-1+c x^2}\right )+b \left (-2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {PolyLog}\left (3,\frac {1+c x^2}{1-c x^2}\right )+2 \left (a+b \tanh ^{-1}\left (c x^2\right )\right ) \text {PolyLog}\left (3,\frac {1+c x^2}{-1+c x^2}\right )+b \left (\text {PolyLog}\left (4,\frac {1+c x^2}{1-c x^2}\right )-\text {PolyLog}\left (4,\frac {1+c x^2}{-1+c x^2}\right )\right )\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.02, size = 0, normalized size = 0.00 \[\int \frac {\left (a +b \arctanh \left (c \,x^{2}\right )\right )^{3}}{x}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b \operatorname {atanh}{\left (c x^{2} \right )}\right )^{3}}{x}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a+b\,\mathrm {atanh}\left (c\,x^2\right )\right )}^3}{x} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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